Past Year Question Spm Mathematics

$\begin{array}{rcl} x(2x-5)&=&2x-1 \\ 2{{x}^{2}}-5x-2x+1&=&0 \\ 2{{x}^{2}}-7x+1&=&0 \\ hence, a=2,b=-7,c&=&1 \\ x&=& \frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a} \\ x&=& \frac{-(-7)\pm \sqrt{{{(-7)}^{2}}-4(2)(1)}}{2(2)} \\ x&=& \frac{7+\sqrt{41}}{4}\text\quad{ or }\quad x=\frac{7-\sqrt{41}}{4} \\ x&=& \underline{3.351}\text\quad{ or }\quad x=\underline{0.149} \\ \end{array}$